請問如何呼叫JqDataHandle.ashx 並傳給他remoteName、tableName、whereString取到某一筆資料?
var remoteName = getInfolightOption($('#dataFormMaster')).remoteName;

var tableName = getInfolightOption($('#dataFormMaster')).tableName;

var queryWord = new Object();

queryWord.whereString = "TKQK10='" + $('#dataFormMasterTKQK10').refval('getValue') + "' AND " + "TKQK03=to_date('" + $('#dataFormMasterTKQK03').datebox('getValue') + "','YYYY/MM/DD')";

$.ajax({

type: "POST",

url: getRemoteUrl(remoteName, tableName, true),

data: { queryWord: $.toJSONString(queryWord) },

cache: false,

async: false,

success: function (data) {

index = $('#dataGridView').datagrid('getRowIndex', $('#dataGridView').datagrid('getSelected'));

var rows = $.parseJSON(data);

if (rows.length > 0) {

$('#dataGridView').datagrid('updateRow', { index: index, row: rows[0] });

}

}

});