如何取得infofileupload上傳時的檔名?
var infofileUpload = $('#dataFormMasterShipCity');

var infofileUploadvalue = $('.info-fileUpload-value', infofileUpload.next())

var infofileUploadfile = $('.info-fileUpload-file', infofileUpload.next())

infofileUploadvalue.val()
是文件名。

infofileUploadfile.val()
是完整路徑。